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If you choose an answer to this question at random, what is the chance you will be correct?
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If you choose an answer to this question at random, what is the chance you will be correct?
50% random answer probability 50% (1) , random (11) , answer (7) , probability (2)

Source: SUBMIT / chan4chan URL: http://flowingdata.com/wp-content/uploads/2011/10/Best-Math-Question-EVAR-625x352.jpg Info: JPG, 34 Kbytes (625x352) Added by: ManWhore (Nov 7, 2011) Category: random NSFW: no Report abuse
anonymule: A)1320625181563
AnotherAnon: B1320625235664
cybersinner: C1320632030524
Anonymous: B.1320632105328
Everdark: D1320635735855
Oldandevil: Your chance of choosing 25% is 2 out of 4 (50%). Your chance of choosing 50% is 1 out of 4 (25%). Your chance of choosing 60% is 1 out of 4 (25%). There is no correct answer.1320636213999
Anonymous: ^ wrong dumbfag - both A and D are correct... DUH!!!1320639176760
oldandevil: ^ The chance of choosing 25% is 50%, therefore you did not choose the correct answer.1320639249518
Anonymous: ^ think about it idiot... and hire an accountant... the CORRECT answer is 25%... one in four...1320640288681
oldandevil: ^ Since 2 out of the 4 answers are "25%" the odds of randomly choosing "25%" is 2 out of 4 or 50%. Why do you find this such a hard concept?1320640615560
Anonymous: ^ Which makes the right answer 50%. Then the chances are 25% again. Forever a loop.1320640672455
oldandevil: ^Correct! At last you understand that there is NO CORRECT ANSWER... exactly as I said in 3999.1320640805343
chumpno1: potato1320652167586
Lickathesplit: The change of choosing the correct answer is 25 % since there are 4 answers and obviously you don't know them otherwise you wouldn't have to guess. Only 1 of the four answers can be correct, two answers are the same but that doesn't change one thing. Only ONE in four answers is correct via logic or random choise.1320652377503

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